Will mark Brainliest if someone can help me!!!!! (Idk if Prinicipal is right 2-5)

[tex]\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$1500\\ r=rate\to r\%\to \frac{r}{100}\dotfill &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1,2,3,4,5 \end{cases}[/tex][tex]\bf A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 1}\implies A=1500(1.04)^1\implies A\approx 1560\\\\\\A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 2}\implies A=1500(1.04)^2\implies A\approx 1622.4\\\\\\A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 3}\implies A=1500(1.04)^3\implies A\approx 1687.3\\\\\\A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 4}\implies A=1500(1.04)^4\implies A\approx 1754.79\\\\\\A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 5}\implies A=1500(1.04)^5\implies A\approx 1824.98[/tex]